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Negative vs positive exponents
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09 Oct 2018, 01:31
09 Oct 2018, 01:31
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Question Stats:
99% (00:25) correct
0% (00:00) wrong based on 17 sessions
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I have a question about this quantitative comparison. According to the book it's C. I think if x = -1 of instance, the answer is no longer 0. So if x is a positive even number of positive odd number, then the answer is 0, but not so with a negative integer. For instance, if x = -1, then the answer is -9.9. So it can't be C.
Am I correct?
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Am I correct?
Quantity A |
Quantity B |
\(\frac{1}{(-1)^x} - (-1)^x\) |
\(0\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: Negative vs positive exponents
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09 Oct 2018, 01:53
09 Oct 2018, 01:53
1
Expert Reply
Monco wrote:
I have a question about this quantitative comparison. According to the book it's C. I think if x = -1 of instance, the answer is no longer 0. So if x is a positive even number of positive odd number, then the answer is 0, but not so with a negative integer. For instance, if x = -1, then the answer is -9.9. So it can't be C.
Am I correct?
Am I correct?
What is \(\frac{1}{(-1)^x}-(-1)^x=(-1)^x(\frac{1}{(-1)^{2x}}-1).....(-1)^x*(\frac{1}{1^x}-1)=(-1)^x*(1-1)=0\)
So irrespective of x answer is ALWAYS 0
Let me take your example..
\(x^{-y}=\frac{1}{x^y}\)..
So \(\frac{1}{(-1)^{-1}}-(-1)^{-1}=1"(-1)^1-\frac{1}{(-1)^1}\)=-1-(-1)=-1+1=0
Hope it helps
Re: Negative vs positive exponents
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09 Oct 2018, 01:58
09 Oct 2018, 01:58
1
Thank you! I really need to review exponents. I totally mixed them up.
