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What is the area of the equilateral triangle if the base BC

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Carcass
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What is the area of the equilateral triangle if the base BC [#permalink] New post   15 Oct 2018, 03:26
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What is the area of the equilateral triangle if the base BC = 6?

(A) \(9 \sqrt{3}\)

(B) \(18 \sqrt{3}\)

(C) \(26 \sqrt{3}\)

(D) \(30 \sqrt{3}\)

(E) \(36 \sqrt{3}\)
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Re: What is the area of the equilateral triangle if the base BC [#permalink] New post   09 Jan 2019, 07:18
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For equilateral triangle area= \(\sqrt{3}/4*a^2\) where a = side
Here, \(\sqrt{3}/4*6^2\)
=\(9 \sqrt{3}\)
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Re: What is the area of the equilateral triangle if the base BC [#permalink] New post   27 Apr 2021, 15:48
Carcass wrote:
Attachment:
#GREpracticequestion What is the area of the equilateral triangle.jpg


What is the area of the equilateral triangle if the base BC = 6?

(A) \(9 \sqrt{3}\)

(B) \(18 \sqrt{3}\)

(C) \(26 \sqrt{3}\)

(D) \(30 \sqrt{3}\)

(E) \(36 \sqrt{3}\)


Useful formula: Area of equilateral triangle = (side²)(√3)/4

In this question, we're told that each side has length 6.

So, area = (6²)(√3)/4
= (36)(√3)/4
= 9√3

Answer: A
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Re: What is the area of the equilateral triangle if the base BC [#permalink]
27 Apr 2021, 15:48
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