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The average (arithmetic mean) bowling score of n bowlers is
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15 Oct 2018, 09:37
15 Oct 2018, 09:37
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The average (arithmetic mean) bowling score of n bowlers is 160. The average of these n scores together with a score of 170 is 161. What is the number of bowlers, n ?
Show: :: Bowlers
9
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Re: The average (arithmetic mean) bowling score of n bowlers is
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15 Oct 2018, 10:20
15 Oct 2018, 10:20
1
Carcass wrote:
The average (arithmetic mean) bowling score of n bowlers is 160. The average of these n scores together with a score of 170 is 161. What is the number of bowlers, n ?
Show: :: Bowlers
9
The average (arithmetic mean) bowling score of n bowlers is 160.
In other words, (sum of all n scores)/n = 160
Multiply both sides by n to get: sum of all n scores = 160n
The average of these n scores together with a score of 170 is 161
In other words: (sum of all n + 1 scores)/(n + 1) = 161
In other words: (sum of first n scores + 170)/(n + 1) = 161
Rewrite as: (160n + 170)/(n + 1) = 161
Multiply both sides by (n + 1) to get: 160n + 170 = 161(n + 1)
Simplify: 160n + 170 = 161n + 161
Solve: n = 9
Answer: 9
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Re: The average (arithmetic mean) bowling score of n bowlers is [#permalink]
15 Oct 2018, 10:20
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