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A salesman sells two identical jewelry boxes at the same pri
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Updated on: 18 Oct 2018, 10:45
Updated on: 18 Oct 2018, 10:45
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Question Stats:
63% (01:42) correct
36% (02:01) wrong based on 71 sessions
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A salesman sells two identical jewelry boxes at the same price to two different stores. at the first store, the price of the jewelry box is decreased by a 10% for a sale, and then increased by 20% for profit. at the second store, the price of the jewelry box is increased by 10% for profit, and then decreased 20% for a sale.
Quantity A |
Quantity B |
The profit on the jewelry box at the first store. |
The percent difference from the jewelry box at the salesman's cost to the jewelry box's final cost at the second store. |
Originally posted by amitmathew on 18 Oct 2018, 00:26.
Last edited by Carcass on 18 Oct 2018, 10:45, edited 1 time in total.
Last edited by Carcass on 18 Oct 2018, 10:45, edited 1 time in total.
Edited by Carcass
Re: Quant Comparison Question - from TPR refresher worksheet
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18 Oct 2018, 00:33
18 Oct 2018, 00:33
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amitmathew wrote:
A salesman sells two identical jewelry boxes at the same price to two different stores. at the first store, the price of the jewelry box is decreased by a 10% for a sale, and then increased by 20% for profit. at the second store, the price of the jewelry box is increased by 10% for profit, and then decreased 20% for a sale.
Quantity A: The profit on the jewelry box at the first store.
Quantity B: The percent difference from the jewelry box at the salesman's cost to the jewelry box's final cost at the second store.
Is B greater?
Quantity A: The profit on the jewelry box at the first store.
Quantity B: The percent difference from the jewelry box at the salesman's cost to the jewelry box's final cost at the second store.
Is B greater?
Let the price be100...
first store
100*(1-0.1)(1+0.2)=100*0.9*1.2=9*12=108
second store
100*(1+0.1)(1-0.2)=100*0.8*1.1=8*11=88
Quantity A: The profit on the jewelry box at the first store.
Profit = \(100*\frac{108-100}{100}\)=8%
Quantity B: The percent difference from the jewelry box at the salesman's cost to the jewelry box's final cost at the second store.
Cost at jewellery box = 100%, and at second store = 88%
So percent difference=|100-88|=12%
So B is greater.
Re: Quant Comparison Question - from TPR refresher worksheet
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18 Oct 2018, 01:13
18 Oct 2018, 01:13
That's what I got. Thanks!
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