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x - y > 0 and x > 1 and √(-)=√x
[#permalink]
16 Aug 2018, 09:03
16 Aug 2018, 09:03
1
00:00
Question Stats:
65% (01:07) correct
34% (01:15) wrong based on 26 sessions
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\(x - y > 0\) and \(x > 1\) and \(\sqrt{(x-y)}=\sqrt{x}-1\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(Y\) |
\(2 \sqrt{x}-1\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: x - y > 0 and x > 1 and √(-)=√−1
[#permalink]
17 Aug 2018, 06:48
17 Aug 2018, 06:48
1
amorphous wrote:
\(x - y > 0\) and \(x > 1\) and \(\sqrt{(x-y)}=\sqrt{-1}\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(Y\) |
\(2 \sqrt{-1}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
I think this question is missing something.
As it stands, we're told that x - y > 0. In other words, x - y is POSITIVE
Then we're told that \(\sqrt{(x-y)}=\sqrt{-1}\)
This means x - y = -1
However, we earlier learned that x - y is POSITIVE
Cheers,
Brent
Re: x - y > 0 and x > 1 and √(-)=√−1
[#permalink]
02 Sep 2018, 20:49
02 Sep 2018, 20:49
GreenlightTestPrep wrote:
amorphous wrote:
\(x - y > 0\) and \(x > 1\) and \(\sqrt{(x-y)}=\sqrt{-1}\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(Y\) |
\(2 \sqrt{-1}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
I think this question is missing something.
As it stands, we're told that x - y > 0. In other words, x - y is POSITIVE
Then we're told that \(\sqrt{(x-y)}=\sqrt{-1}\)
This means x - y = -1
However, we earlier learned that x - y is POSITIVE
Cheers,
Brent
yes the question was incomplete, I have changed it.
