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A parabola follows the function f(x)=x2+ax+b. Here a and b a
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Updated on: 14 Nov 2018, 07:19
Updated on: 14 Nov 2018, 07:19
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A parabola follows the function f(x)=x^2+ax+b. Here a and b are constants
Points (0,1) and (1,1) both lie on the parabola. What is the distance between a point A with coordinates (a,b) and the origin (0,0)?
Answer in upto two decimal places.
Points (0,1) and (1,1) both lie on the parabola. What is the distance between a point A with coordinates (a,b) and the origin (0,0)?
Answer in upto two decimal places.
Show: ::
\(\sqrt{2}=1.41\)
Re: A parabola follows the function f(x)=x2+ax+b. Here a and b a
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14 Nov 2018, 07:17
14 Nov 2018, 07:17
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Sawant91 wrote:
A parabola follows the function f(x)=x^2+ax+b. Here a and b are constants
Points (0,1) and (1,1) both lie on the parabola. What is the distance between a point A with coordinates (a,b) and the origin (0,0)?
Answer in upto two decimal places.
Points (0,1) and (1,1) both lie on the parabola. What is the distance between a point A with coordinates (a,b) and the origin (0,0)?
Answer in upto two decimal places.
Point (0,1) says f(x)=x^2+ax+b \(=> 1=0^2+0*a+b....b=1\)
Point (1,1) says f(x)=x^2+ax+b \(=> 1=1^2+1*a+b....a+b=0\) but b=1, so a+1=0...a=-1
coordinates (a,b) = (-1,1)
distance from (0,0) is \(\sqrt{(0-(-1))^2+(0-1)^2}=\sqrt{2}=1.41\)
Re: A parabola follows the function f(x)=x2+ax+b. Here a and b a
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05 Jul 2021, 01:05
05 Jul 2021, 01:05
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