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Re: The center of a circle is (10, –3). The point (10, 9) is out
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19 Nov 2018, 14:11
Explanation
Given that (10,9 ) is out side the circle centered at (10, –3). A distance between these two points are:
\(d1 = \sqrt{(10-10)^2+(9-(-3))^2}=12\). So the radius is less than 12.
Similarly, given that (6,-3) is out side the circle centered at (10, –3). A distance between these two points are:
\(d2 = \sqrt{(10-6)^2+(-3-(-3))^2}=4\). So the radius is more than 4.
So the radius is an integer between 4 and 12 hence there are 7 integers between 4 and 12.
Hence A.