Which of the following lines intersects the vertical line x = 3 between (3, 1) and (3, 2)?

Look at the figure attached for visualizing the question.
Now, if a line intersects the line x=3, the x-coordinate will always be 3 and y should be between 1 and 2..

Let us substitute the value of x as 3 to see which option gives y between 2 and 3

A. $y=(\frac{3}{5})x=(\frac{3}{5})*3=\frac{9}{5}= 1+\frac{4}{5}........$, x is between 1 and 2 YES

B. $y=(\frac{3}{7})x+1=(\frac{9}{7})+1=(\frac{2}{7})+2......$, thus between 2 and 3... No

C. $y=(\frac{1}{5})x+\frac{6}{5}=(\frac{1}{5})*3+\frac{6}{5}=\frac{9}{5}$, x is between 1 and 2...Yes

D. $y=-(\frac{3}{2})x+5=5-(\frac{9}{2})=\frac{1}{2}$, thus x <1...No

E. $y=-(\frac{1}{4})x+3=3-(\frac{3}{4})=2+\frac{1}{4}$, thus between 2 and 3...No

A and C