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Oranges are bought at the rate of 10 for
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Updated on: 05 Dec 2018, 08:54
Updated on: 05 Dec 2018, 08:54
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Question Stats:
72% (01:47) correct
27% (00:57) wrong based on 11 sessions
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Oranges are bought at the rate of 10 for $25 and sold at the rate of 9 for $25. The profit is:
a) \(9 \frac{1}{11}\) %
b) \(10\)%
c) \(11 \frac{1}{9}\) %
d) \(12 \frac{1}{2}\) %
e) \(2 \frac{1}{2}\) %
a) \(9 \frac{1}{11}\) %
b) \(10\)%
c) \(11 \frac{1}{9}\) %
d) \(12 \frac{1}{2}\) %
e) \(2 \frac{1}{2}\) %
Re: Oranges are bought at the rate of 10 for
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05 Dec 2018, 04:14
05 Dec 2018, 04:14
Expert Reply
Please, follow the rules for posting on the board: such as a proper title and not profit loss.
Moreover, Rs stands for ?? and also the question misses an option.
Regards
Moreover, Rs stands for ?? and also the question misses an option.
Regards
Re: Oranges are bought at the rate of 10 for
[#permalink]
05 Dec 2018, 08:54
05 Dec 2018, 08:54
Expert Reply
nadeem790 wrote:
Oranges are bought at the rate of 10 for $25 and sold at the rate of 9 for $25. The profit is:
a) \(9 \frac{1}{11}\) %
b) \(10\)%
c) \(11 \frac{1}{9}\) %
d) \(12 \frac{1}{2}\) %
e) \(2 \frac{1}{2}\) %
a) \(9 \frac{1}{11}\) %
b) \(10\)%
c) \(11 \frac{1}{9}\) %
d) \(12 \frac{1}{2}\) %
e) \(2 \frac{1}{2}\) %
Cost price = the rate of 10 for $25= \(\frac{25}{10}\) and
Selling price = sold at the rate of 9 for $25= \(\frac{25}{9}\)
Profit = \((\frac{25}{9}-\frac{25}{10})/\frac{25}{10}=\frac{25}{90}/\frac{25}{10}=\frac{1}{9}\)
Profit % = \(100*\frac{1}{9}\)= \(11 \frac{1}{9}\) %
C
