Explanation

In this problem, Tarik is not picking 1 chip out of all 12. Rather, he is picking 1 chip out of 6 green ones, and then picking another chip out of 6 blue ones. There are 3 green chips with numbers less than 4, so Tarik has a $\frac{3}{6}$ chance of selecting a green chip showing a number less than 4.

Likewise, Tarik has a $\frac{3}{6}$ chance of selecting a blue chip showing a number less than 4.

Therefore, Quantity A is equal to $\frac{3}{6}\times \frac{3}{6}=\frac{1}{2}\times\frac{1}{2}=\frac{1}{4}$. Quantity B is greater.