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abc > 0

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Carcass
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abc > 0 [#permalink] New post   24 Sep 2018, 03:35
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\(abc > 0\)

Quantity A
Quantity B
c(a + b)
abc


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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D
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ARIJOSHI
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Re: abc > 0 [#permalink] New post   11 Jan 2019, 23:51
1
Given:
abc > 0 which implies that,
Out of a,b,c either two of the variables can be negative or all of the three variables can be positive.
Suppose a=1, b=2 and c=3.
We get, A > B ( A=9 and B=6)
Suppose a= -1, b=-2 and c=3
We get, B > A ( A=-9 and B=3)
Hence, the answer is D.
Please rectify if the process is wrong.

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chetan2u
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Re: abc > 0 [#permalink] New post   12 Jan 2019, 04:36
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Carcass wrote:
\(abc > 0\)

Quantity A
Quantity B
c(a + b)
abc


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.



A very straight forward solution, even if we take all as positive..
(1) Let \(a=b=c=3\)
A=(c(a + b))=\(3(3+3)=18\)
B=(abc)=\(3*3*3=27\)
so B>A
(2) Let \(a=b=c=1\)
A=(c(a + b))=\(1(1+1)=2\)
B=(abc)=\(1*1*1=1\)
so A>B

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Re: abc > 0 [#permalink] New post   26 May 2021, 04:04
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We definitely know that quantity abc > 0 hence quantity B is positive , But in Quantity a, we donot know about the individual variable sign. and we cant compare the these quantity.
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Re: abc > 0 [#permalink]
26 May 2021, 04:04
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