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Sn = 3n + 3 Sequence S is defined for each integer n such th
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30 Aug 2018, 07:37
30 Aug 2018, 07:37
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22% (01:47) wrong based on 187 sessions
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\(S_n = 3n + 3\)
Sequence S is defined for each integer n such that
0 < n < 10,000.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Sequence S is defined for each integer n such that
0 < n < 10,000.
Quantity A |
Quantity B |
The median of sequence S |
The mean of sequence S |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: Sn = 3n + 3 Sequence S is defined for each integer n such th
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04 Sep 2018, 10:36
04 Sep 2018, 10:36
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sandy wrote:
\(S_n = 3n + 3\)
Sequence S is defined for each integer n such that
0 < n < 10,000.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Sequence S is defined for each integer n such that
0 < n < 10,000.
Quantity A |
Quantity B |
The median of sequence S |
The mean of sequence S |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Let's examine a few terms in the sequence.
GIVEN: term_n = 3n + 3
So, term_1 = 3(1) + 3 = 6
term_2 = 3(2) + 3 = 9
term_3 = 3(3) + 3 = 12
term_4 = 3(4) + 3 = 15
term_5 = 3(5) + 3 = 18
etc
So, the sequence looks like this: 6, 9, 12, 15, 18, . . .
KEY CONCEPT: "In a set where the numbers are equally spaced, the mean will equal the median."
For example, in each of the following sets, the mean and median are equal:
{7, 9, 11, 13, 15}
{-1, 4, 9, 14}
{3, 4, 5, 6}
Since the numbers in the given set {6, 9, 12, 15, 18, . . .} are EQUALLY SPACED, the mean must equal the median
Answer: C
Cheers,
Brent
General Discussion
Re: Sn = 3n + 3 Sequence S is defined for each integer n such th
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04 Sep 2018, 01:53
04 Sep 2018, 01:53
Answer is C
