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s = (t + r)^2
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16 Jan 2019, 17:39
16 Jan 2019, 17:39
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Question Stats:
75% (01:05) correct
25% (01:13) wrong based on 96 sessions
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\(s = (t + r)^2\)
\(s = 4\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\(s = 4\)
Quantity A |
Quantity B |
\(2-r\) |
\(t\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: s = (t + r)^2
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16 Jan 2019, 21:20
16 Jan 2019, 21:20
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Carcass wrote:
\(s = (t + r)^2\)
\(s = 4\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\(s = 4\)
Quantity A |
Quantity B |
2-r |
t |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Explanation::
\(s = (t + r)^2\)
or \((t + r)^2 = 4\)
or t + r = 2 and - 2
Now when
1. t + r = 2 , or t = 2 - r
then Qty A = Qty B
2. when t + r = -2 or t = -2 - r
then Qty A > Qty B
Hence Option D
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Re: s = (t + r)^2
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11 Aug 2020, 07:48
11 Aug 2020, 07:48
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Carcass wrote:
\(s = (t + r)^2\)
\(s = 4\)
\(s = 4\)
Quantity A |
Quantity B |
2-r |
t |
Here's an approach that starts by rearranging the two quantities via the strategy of matching operations (my favorite Quantitative Comparison strategy)
Given:
Quantity A: 2 - r
Quantity B: t
Add r do both quantities to get:
Quantity A: 2
Quantity B: t + r
Given: (t + r)² = s and s = 4
In the first equation, replace s with 4 to get: (t + r)² = 4
This means EITHER (t + r) = 2 OR (t + r) = -2
If t + r = 2, we get:
Quantity A: 2
Quantity B: t + r = 2
And this case, the two quantities are equal
If t + r = -2, we get:
Quantity A: 2
Quantity B: t + r = -2
And this case, Quantity A is greater
Answer: D
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