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Let the lengths of the sides of a triangle be represented by
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24 Jan 2019, 06:14
24 Jan 2019, 06:14
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Question Stats:
80% (01:01) correct
19% (00:57) wrong based on 89 sessions
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Let the lengths of the sides of a triangle be represented by \(x + 3\), \(2x – 3\), and \(3x – 5\). If the perimeter of the triangle is 25, what is the length of the shortest side?
A. 5
B. 6
C. 7
D. 8
E. 10
A. 5
B. 6
C. 7
D. 8
E. 10
Re: Let the lengths of the sides of a triangle be represented by
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25 Jan 2019, 19:31
25 Jan 2019, 19:31
1
From question,
\(x+3 + 2x-3 + 3x - 5 = 25\)
or, \(6x - 5 = 25\)
or, \(6x = 30\)
or,\(x = 5\)
let us find the length of each sides.
\(x+3 = 8\)
\(2x-3 = 7\)
\(3x-5 = 10\)
Therefore the smallest side is 7.
\(x+3 + 2x-3 + 3x - 5 = 25\)
or, \(6x - 5 = 25\)
or, \(6x = 30\)
or,\(x = 5\)
let us find the length of each sides.
\(x+3 = 8\)
\(2x-3 = 7\)
\(3x-5 = 10\)
Therefore the smallest side is 7.
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Re: Let the lengths of the sides of a triangle be represented by
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30 Dec 2024, 19:18
30 Dec 2024, 19:18
Perimeter of a triangle = Sum of all the sides
=> x + 3 + 2x - 3 + 3x - 5 = 25
=> 6x - 5 = 25
=> 6x = 30
=> x = 30/6 = 5
So, the sides are
Length of the shortest side = 7
So, Answer will be C
Hope it helps!
=> x + 3 + 2x - 3 + 3x - 5 = 25
=> 6x - 5 = 25
=> 6x = 30
=> x = 30/6 = 5
So, the sides are
- x + 3 = 5 + 3 = 8
2x - 3 = 2*5 - 3 = 10 - 3 = 7
3x - 5 = 3*5 - 5 = 15 - 5 = 10
Length of the shortest side = 7
So, Answer will be C
Hope it helps!
