GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
x>0 and 2x/3<7
[#permalink]
07 Jun 2017, 00:52
07 Jun 2017, 00:52
Expert Reply
00:00
Question Stats:
68% (00:41) correct
31% (00:45) wrong based on 183 sessions
Hide Show timer Statistics
\(x >0\) and \(\frac{2x}{3} < 7\)
Quantity A |
Quantity B |
\(x^2\) |
\(100\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
x>0 and 2x/3<7
[#permalink]
14 Jun 2017, 06:25
14 Jun 2017, 06:25
1
Carcass wrote:
\(x>0\) and \(\frac{2x}{3}<7\)
Quantity A |
Quantity B |
x^2 |
100 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Take: 2x/3 < 7
Multiply both sides by 3 to get: 2x < 21
Divide both sides by 2 to get: x < 10.5
We're also told that x > 0, which is the same as 0 < x
We can COMBINE the inequalities to get: 0 < x < 10.5
In other words, x is BETWEEN 0 and 10.5
We're comparing x² and 100
Let's PLUG IN some values for x
x = 1
We get:
Quantity A: 1² = 1
Quantity B: 100
Quantity B is greater
x = 10
We get:
Quantity A: 10² = 100
Quantity B: 100
The quantities are equal
Answer: D
Re: x>0 and 2x/3<7
[#permalink]
11 Feb 2019, 20:26
11 Feb 2019, 20:26
2x/3 < 7
Solving further 2x < 21, hence x < 10.5
So 10.5<x>0
So we cant really determine the value of x
Answer is D
Solving further 2x < 21, hence x < 10.5
So 10.5<x>0
So we cant really determine the value of x
Answer is D
