GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
jm + kn + km + jn =12 and j + k=4
[#permalink]
28 Feb 2019, 11:11
28 Feb 2019, 11:11
Expert Reply
00:00
Question Stats:
85% (00:38) correct
14% (00:44) wrong based on 61 sessions
Hide Show timer Statistics
\(jm + kn + km + jn =12\) and \(j + k=4\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(j+ k\) |
\(m + n\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: jm + kn + km + jn =12 and j + k=4
[#permalink]
28 Feb 2019, 12:14
28 Feb 2019, 12:14
1
jm + kn + km + jn = 12
jm + jn + kn + km = 12
j(m+n) + k(n+m) = 12
(m+n)(j+k) = 12 (m+n is the same as n+m)
(m+n)(4) = 12 (we're given that j+k is 4)
m+n = 3
Because m+n = 3 < j+k = 4, j+k is greater. Answer is A
jm + jn + kn + km = 12
j(m+n) + k(n+m) = 12
(m+n)(j+k) = 12 (m+n is the same as n+m)
(m+n)(4) = 12 (we're given that j+k is 4)
m+n = 3
Because m+n = 3 < j+k = 4, j+k is greater. Answer is A
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: jm + kn + km + jn =12 and j + k=4
[#permalink]
21 Aug 2020, 06:29
21 Aug 2020, 06:29
1
Carcass wrote:
\(jm + kn + km + jn =12\) and \(j + k=4\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(j+ k\) |
\(m + n\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
We can use a strategy known as factoring in parts
Given: jm + kn + km + jn = 12
Rearrange as follows: jm + km + jn + kn = 12
Factor in parts as follows: m(j + k) + n(j + k) = 12
Notice that both parts contain (j + k), so we can combine these terms in the same way we would take 3x + 2x and combine the terms to get (3 + 2)x, which is the same as 5x.
When we combine the terms we get: (m + n)(j + k) = 12
Also given: j + k = 4
So we can replace j + k with 4 to get: (m + n)(4) = 12
Divide both sides of the equation by 4 to get: m + n = 3
We now have:
Quantity A: 4
Quantity B: 3
Answer: A
