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jm + kn + km + jn =12 and j + k=4
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28 Feb 2019, 11:11
28 Feb 2019, 11:11
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\(jm + kn + km + jn =12\) and \(j + k=4\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(j+ k\) |
\(m + n\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: jm + kn + km + jn =12 and j + k=4
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28 Feb 2019, 12:14
28 Feb 2019, 12:14
1
jm + kn + km + jn = 12
jm + jn + kn + km = 12
j(m+n) + k(n+m) = 12
(m+n)(j+k) = 12 (m+n is the same as n+m)
(m+n)(4) = 12 (we're given that j+k is 4)
m+n = 3
Because m+n = 3 < j+k = 4, j+k is greater. Answer is A
jm + jn + kn + km = 12
j(m+n) + k(n+m) = 12
(m+n)(j+k) = 12 (m+n is the same as n+m)
(m+n)(4) = 12 (we're given that j+k is 4)
m+n = 3
Because m+n = 3 < j+k = 4, j+k is greater. Answer is A
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Re: jm + kn + km + jn =12 and j + k=4
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21 Aug 2020, 06:29
21 Aug 2020, 06:29
1
Carcass wrote:
\(jm + kn + km + jn =12\) and \(j + k=4\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(j+ k\) |
\(m + n\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
We can use a strategy known as factoring in parts
Given: jm + kn + km + jn = 12
Rearrange as follows: jm + km + jn + kn = 12
Factor in parts as follows: m(j + k) + n(j + k) = 12
Notice that both parts contain (j + k), so we can combine these terms in the same way we would take 3x + 2x and combine the terms to get (3 + 2)x, which is the same as 5x.
When we combine the terms we get: (m + n)(j + k) = 12
Also given: j + k = 4
So we can replace j + k with 4 to get: (m + n)(4) = 12
Divide both sides of the equation by 4 to get: m + n = 3
We now have:
Quantity A: 4
Quantity B: 3
Answer: A
