Last visit was: 17 Dec 2024, 22:55 It is currently 17 Dec 2024, 22:55

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 30349
Own Kudos [?]: 36746 [28]
Given Kudos: 26080
Send PM
Most Helpful Expert Reply
avatar
Manager
Manager
Joined: 04 Feb 2019
Posts: 204
Own Kudos [?]: 422 [11]
Given Kudos: 0
Send PM
General Discussion
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12225 [2]
Given Kudos: 136
Send PM
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12225 [0]
Given Kudos: 136
Send PM
Re: A sum of money was distributed among Lyle, Bob, and Chloe. F [#permalink]
Carcass wrote:
A sum of money was distributed among Lyle, Bob, and Chloe. First, Lyle received $ 4 plus one-half of what remained. Next, Bob received $ 4 plus one-third of what remained. Finally, Chloe received the remaining $ 32. How many dollars did Bob receive?

A. 10

B. 20

C. 26

D. 40

E. 52


Another approach:

This time, let K = the money REMAINING after Ann has received her portion AND after Bob has taken $4.
At this point, Bob receives 1/3 of K, and Chloe gets the rest.
This means that Chloe receives 2/3 of K

Since Chloe receives $32, we can say that: (2/3)K = 32
Multiply both sides by 3/2 to get: K = 48

Since Bob receives 1/3 of K plus $4, we can see that the amount Bob gets = (1/3)(48) + 4 = $20

Answer: B

Cheers,
Brent
User avatar
Manager
Manager
Joined: 19 Nov 2018
Posts: 102
Own Kudos [?]: 159 [0]
Given Kudos: 0
Send PM
Re: A sum of money was distributed among Lyle, Bob, and Chloe. F [#permalink]
1
I looked at Magoosh's and Brent's solution, which makes sense and is relatively quick. When I tried it I went about it a long way. Specifically, I thought that:

Lyle + Bob + Chloe = Total

I could write Lyle and Bob in terms of Total with the given info and write in 32 for Chloe and then solve for Total. With that I could find Bob.

That was the idea. You can see in the attached calculations I got the wrong answer. I don't know why. Yes, in the future I will do the problem the quick way, as shown by others, but if someone could tell me where I went wrong in my long calculations I would appreciate it (or maybe their is a conceptual flaw in my thinking about it)
Attachments

daum_equation_1565215671335.png
daum_equation_1565215671335.png [ 165.37 KiB | Viewed 23151 times ]

Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12225 [0]
Given Kudos: 136
Send PM
Re: A sum of money was distributed among Lyle, Bob, and Chloe. F [#permalink]
Image

T - (0.5T + 2) - 4 simplifies to be T - 0.5T - 2 - 4

Cheers,
Brent
User avatar
Manager
Manager
Joined: 19 Nov 2018
Posts: 102
Own Kudos [?]: 159 [0]
Given Kudos: 0
Send PM
Re: A sum of money was distributed among Lyle, Bob, and Chloe. F [#permalink]
Thank you very much Brent.
User avatar
Manager
Manager
Joined: 19 Nov 2018
Posts: 102
Own Kudos [?]: 159 [1]
Given Kudos: 0
Send PM
Re: A sum of money was distributed among Lyle, Bob, and Chloe. F [#permalink]
1
Here is the corrected version if anyone's interested. (Of course, as I said before, it's too long. Use the other method)
Attachments

daum_equation_1565287061919.png
daum_equation_1565287061919.png [ 180.97 KiB | Viewed 22933 times ]

User avatar
Director
Director
Joined: 22 Jun 2019
Posts: 521
Own Kudos [?]: 721 [0]
Given Kudos: 161
Send PM
Re: A sum of money was distributed among Lyle, Bob, and Chloe. F [#permalink]
Carcass wrote:
A sum of money was distributed among Lyle, Bob, and Chloe. First, Lyle received $ 4 plus one-half of what remained. Next, Bob received $ 4 plus one-third of what remained. Finally, Chloe received the remaining $ 32. How many dollars did Bob receive?

A. 10

B. 20

C. 26

D. 40

E. 52



Lets, we (L, B, and C) have total 100$.

Now L received 4 + \(\frac{1}{2}\) of 96 ; (96, because after receiving 4 from 100, remaining is 96);

After that B received 4 + \(\frac{1}{3}\) of 48 ; (48, because after receiving \(\frac{1}{2 }\)of 96 we have remaining 48 only)

Now, we have remain only 32 which is C received. (32, because \(\frac{48}{3}\) = 16; 48 - 16 = 32 remaining lastly )

So, from B, ( 4 + \(\frac{1}{3}\) 48 ), we get, 4 + 16 = 20.
Intern
Intern
Joined: 07 Apr 2022
Posts: 32
Own Kudos [?]: 32 [0]
Given Kudos: 1
Send PM
A sum of money was distributed among Lyle, Bob, and Chloe. F [#permalink]
Quick and easy method:
Since Bob received $4 plus 1/3 of the remainder, the total between Bob and Chloe can be represented as $32=2/3(T-4).
Simplify.
96=2(T-4), 48=T-4, T=52
Then, subtract Chloe's sum from the total between Bob and Chloe.
52-32=$20
B
Intern
Intern
Joined: 15 Oct 2022
Posts: 14
Own Kudos [?]: 18 [1]
Given Kudos: 70
Location: India
Concentration: Technology, Finance
GPA: 3.52
WE:Analyst (Computer Software)
Send PM
Re: A sum of money was distributed among Lyle, Bob, and Chloe. F [#permalink]
1
Lets say initial amount is x.
Lyle gets an amount of 4+(x-4)/2.
Bob gets an amount of 4+(x-4)/(2x3).
Chloe gets an amount of 2/3 * (x-4)/2 = (x-4)/3 which is in turn = 32 (given in question). This implies (x-4)/6 = 16 -- (Eqn 1)
Therefore, without even solving for x, we can get Bob's amount = 4+(x-4)/6 = 4+16 (Using Eqn 1) = 20.
Hence, 20 is the answer.
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5090
Own Kudos [?]: 76 [0]
Given Kudos: 0
Send PM
Re: A sum of money was distributed among Lyle, Bob, and Chloe. F [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
Re: A sum of money was distributed among Lyle, Bob, and Chloe. F [#permalink]
Moderators:
GRE Instructor
88 posts
GRE Forum Moderator
37 posts
Moderator
1115 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne