GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If xy ≠ 0,
[#permalink]
16 Mar 2019, 01:33
16 Mar 2019, 01:33
Expert Reply
00:00
Question Stats:
99% (00:19) correct
0% (00:00) wrong based on 7 sessions
Hide Show timer Statistics
If \(xy ≠ 0\), \(\frac{1 - x}{xy} =\)
A. \(\frac{1}{xy} - \frac{1}{y}\)
B. \(\frac{x}{y} - \frac{1}{x}\)
C. \(\frac{1}{xy} - 1\)
D. \(\frac{1}{xy} - \frac{x^2}{y}\)
E. \(\frac{1}{x} - \frac{1}{y}\)
A. \(\frac{1}{xy} - \frac{1}{y}\)
B. \(\frac{x}{y} - \frac{1}{x}\)
C. \(\frac{1}{xy} - 1\)
D. \(\frac{1}{xy} - \frac{x^2}{y}\)
E. \(\frac{1}{x} - \frac{1}{y}\)
Re: If xy ≠ 0,
[#permalink]
20 Mar 2019, 15:06
20 Mar 2019, 15:06
Expert Reply
When we add or subtract fractions, we have to keep the denominator the same and only add or subtract the numerators. When we do that operation in reverse, we can break our single fraction into two smaller fractions:
\(\frac{1-x}{xy} = \frac{1}{xy} - \frac{x}{xy}\)
Now, since we have an x in the numerator and denominator of the second fraction, we can cancel those out:
\(\frac{1}{xy} - \frac{1}{y}\)
\(\frac{1-x}{xy} = \frac{1}{xy} - \frac{x}{xy}\)
Now, since we have an x in the numerator and denominator of the second fraction, we can cancel those out:
\(\frac{1}{xy} - \frac{1}{y}\)
gmatclubot
Re: If xy ≠ 0, [#permalink]
20 Mar 2019, 15:06
Moderators:
