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The arithmetic mean of a, b, c, and d is 14

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Carcass
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The arithmetic mean of a, b, c, and d is 14 [#permalink] New post   21 Mar 2019, 11:03
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The arithmetic mean of a, b, c, and d is 14.

Quantity A
Quantity B
\(32\)
The arithmetic mean of \(a + 3b + 2d\) and \(a - b + 2c - 48\)


Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
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GreenlightTestPrep
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The arithmetic mean of a, b, c, and d is 14 [#permalink] New post   22 Mar 2019, 07:20
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Carcass wrote:
The arithmetic mean of a, b, c, and d is 14.

Quantity A
Quantity B
\(32\)
The arithmetic mean of \(a + 3b + 2d\) and \(a - b + 2c - 48\)


Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.


GIVEN: The arithmetic mean of a, b, c, and d is 14
In other words: (a + b + c + d)/4 = 14
Multiply both sides by 4 to get: a + b + c + d = 56

The mean of a + 3b + 2d and a - b + 2c - 48 = [(a + 3b + 2d) + (a - b + 2c - 48)]/2
= [2a + 2b + 2c + 2d - 48]/2
= a + b + c + d - 24
= 56 - 24
= 32

We get:
QUANTITY A: 32
QUANTITY B: 32

Answer: C

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