Looking at the two figures we can find the y-intercept or c.

for fig(1) when x = 0 y = 2 so c =2
for fig(2) when x=0 y = 1 so c = 1

now we can also find the slope of the two function by looking at the figures.
fig(1) slope = change in y / change in x
Hence, slope = \(\frac{2}{2}\) =1

similarly slope of fig(2) = change in y/change in x
Hence, slope = \(\frac{1}{1}\) = 1

now its all about putting the information in the eqn.
for fig(1) using point slope form for f(10) we get,

\(y = mx + c\)
or, \(y = 1(10) + 2\)
or, \(y = 10+2 = 12\)

while for fig(2) for g(10) using point slope form we get,

\(y = 10(1) + 1\)
or, \(y = 11\)