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A box contains only red, white, and blue marbles. Twenty per
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07 Apr 2019, 09:45
07 Apr 2019, 09:45
Expert Reply
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Question Stats:
81% (00:45) correct
18% (01:08) wrong based on 80 sessions
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A box contains only red, white, and blue marbles. Twenty percent of the marbles are blue. Of the remaining marbles, one-quarter are red.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The number of red marbles |
One-third the number of white marbles |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: A box contains only red, white, and blue marbles. Twenty per
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24 Jun 2019, 08:57
24 Jun 2019, 08:57
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If t is total, then:
0.2 * t = blue; remaining 80% or 0.8 * t = r + w;
One quarter or 1/4 of the REMAINING are red which is 0.8 * t * 1/4.
We have remaining 0.8 * t * 3/4 for white.
One-third of white marbles is (0.8 * t * 3/4) / 3 = 0.8 * t * 1/4 = number of red marbles.
Answer is C.
0.2 * t = blue; remaining 80% or 0.8 * t = r + w;
One quarter or 1/4 of the REMAINING are red which is 0.8 * t * 1/4.
We have remaining 0.8 * t * 3/4 for white.
One-third of white marbles is (0.8 * t * 3/4) / 3 = 0.8 * t * 1/4 = number of red marbles.
Answer is C.
Re: A box contains only red, white, and blue marbles. Twenty per
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11 Jul 2019, 21:14
11 Jul 2019, 21:14
i tried doing this taking 45 marbles , but i am not getting C as an answer
20% of 45 is 9(blue marbles)
1/3rd of the remaining i.e 1/3*36 is 12(red marbles)
remaining are white i.e 24 marbles...1/3 of white marbles is 1/3*24 is 8
so, A>B
20% of 45 is 9(blue marbles)
1/3rd of the remaining i.e 1/3*36 is 12(red marbles)
remaining are white i.e 24 marbles...1/3 of white marbles is 1/3*24 is 8
so, A>B
