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Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
If x and y are distinct prime numbers, which of the followin
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08 Apr 2019, 09:41
08 Apr 2019, 09:41
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If x and y are distinct prime numbers, which of the following could be true?
A. \(\frac{x^y}{y}\) is an odd integer
B. \(x^2y^3=x^2\)
C. \(\frac{y^x}{4}\) is an even integer
D. \(\frac{xy}{2}\) is an even integer
E. \(x^y=y^x\)
A. \(\frac{x^y}{y}\) is an odd integer
B. \(x^2y^3=x^2\)
C. \(\frac{y^x}{4}\) is an even integer
D. \(\frac{xy}{2}\) is an even integer
E. \(x^y=y^x\)
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If x and y are distinct prime numbers, which of the followin
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09 Apr 2019, 17:31
09 Apr 2019, 17:31
1
GreenlightTestPrep wrote:
If x and y are distinct prime numbers, which of the following could be true?
A. \(\frac{x^y}{y}\) is an odd integer
B. \(x^2y^3=x^2\)
C. \(\frac{y^x}{4}\) is an even integer
D. \(\frac{xy}{2}\) is an even integer
E. \(x^y=y^x\)
A. \(\frac{x^y}{y}\) is an odd integer
B. \(x^2y^3=x^2\)
C. \(\frac{y^x}{4}\) is an even integer
D. \(\frac{xy}{2}\) is an even integer
E. \(x^y=y^x\)
The keyword here is COULD.
Scanning the answer choices, I see that C could be true.
If x = 2 and y = 3, then (x^y)/4 = (2³)/4 = 2, and 2 IS an even integer.
Answer: C
Cheers,
Brent
Re: If x and y are distinct prime numbers, which of the followin
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04 Jul 2019, 03:34
04 Jul 2019, 03:34
2
GreenlightTestPrep wrote:
GreenlightTestPrep wrote:
If x and y are distinct prime numbers, which of the following could be true?
A. \(\frac{x^y}{y}\) is an odd integer
B. \(x^2y^3=x^2\)
C. \(\frac{y^x}{4}\) is an even integer
D. \(\frac{xy}{2}\) is an even integer
E. \(x^y=y^x\)
A. \(\frac{x^y}{y}\) is an odd integer
B. \(x^2y^3=x^2\)
C. \(\frac{y^x}{4}\) is an even integer
D. \(\frac{xy}{2}\) is an even integer
E. \(x^y=y^x\)
The keyword here is COULD.
Scanning the answer choices, I see that C could be true.
If x = 2 and y = 3, then (x^y)/4 = (2³)/4 = 2, and 2 IS an even integer.
Answer: C
Cheers,
Brent
Hi, your OA stated that it is D, please correct it
