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-101^102

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Carcass
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-101^102 [#permalink] New post   20 Oct 2017, 02:42
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98% (00:11) correct 1% (00:23) wrong based on 133 sessions

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Quantity A
Quantity B
\((-101)^{102}\)
\((-102)^{101}\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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A
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IlCreatore
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Re: -101^102 [#permalink] New post   20 Oct 2017, 04:58
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Without computations, quantity A is elevated to an even exponent, thus the result is positive. Quantity B, instead, is elevated to an odd exponent, thus the result is still negative.

Quantity A is greater!
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Re: -101^102 [#permalink] New post   22 Apr 2019, 17:52
Carcass wrote:



Quantity A
Quantity B
\((-101)^{102}\)
\((-102)^{101}\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Rule #1: ODD exponents preserve the sign of the base.
So, (NEGATIVE)^(ODD integer) = NEGATIVE
and (POSITIVE)^(ODD integer) = POSITIVE

Rule #1: An EVEN exponent always yields a positive result (unless the base = 0)
So, (NEGATIVE)^(EVEN integer) = POSITIVE
and (POSITIVE)^(EVEN integer) = POSITIVE

By rule #1, Quantity A is POSITIVE
By rule #2, Quantity B is NEGATIVE

Answer: A

Cheers,
Brent
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Re: -101^102 [#permalink]
22 Apr 2019, 17:52
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