GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
x=1/1+1/1+1/2
[#permalink]
24 Apr 2019, 00:59
24 Apr 2019, 00:59
Expert Reply
00:00
Question Stats:
92% (00:31) correct
7% (00:48) wrong based on 153 sessions
Hide Show timer Statistics
\(x= \frac{1}{1+\frac{1}{1+\frac{1}{2}}}\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x |
1 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
x=1/1+1/1+1/2
[#permalink]
24 Apr 2019, 10:10
24 Apr 2019, 10:10
2
Carcass wrote:
\(x= \frac{1}{1+\frac{1}{1+\frac{1}{2}}}\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x |
1 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Key concept: 1/(a/b) = b/a
So, \(x= \frac{1}{1+\frac{1}{1+\frac{1}{2}}}\)
\(= \frac{1}{1+\frac{1}{\frac{2}{2}+\frac{1}{2}}}\)
\(= \frac{1}{1+\frac{1}{\frac{3}{2}}}\)
\(= \frac{1}{1+\frac{2}{3}}\)
\(= \frac{1}{\frac{3}{3}+\frac{2}{3}}\)
\(= \frac{1}{\frac{5}{3}}\)
\(= \frac{3}{5}\)
We get:
QUANTITY A: \(= \frac{3}{5}\)
QUANTITY B: \(1\)
Answer: B
Cheers,
Brent
x=1/1+1/1+1/2
[#permalink]
25 Jul 2019, 09:21
25 Jul 2019, 09:21
3
Hi Brent,
I really like your explanations.
As you mentioned in another post. We just need to see that in denominator we are adding something to 1, which makes the denominator greater than 1 and the overall fraction less than 1.
Hence, B>A.
Key concept: 1/(a/b) = b/a
So, \(x= \frac{1}{1+\frac{1}{1+\frac{1}{2}}}\)
\(= \frac{1}{1+\frac{1}{\frac{2}{2}+\frac{1}{2}}}\)
\(= \frac{1}{1+\frac{1}{\frac{3}{2}}}\)
\(= \frac{1}{1+\frac{2}{3}}\)
\(= \frac{1}{\frac{3}{3}+\frac{2}{3}}\)
\(= \frac{1}{\frac{5}{3}}\)
\(= \frac{3}{5}\)
We get:
QUANTITY A: \(= \frac{3}{5}\)
QUANTITY B: \(1\)
Answer: B
Cheers,
Brent
I really like your explanations.
As you mentioned in another post. We just need to see that in denominator we are adding something to 1, which makes the denominator greater than 1 and the overall fraction less than 1.
Hence, B>A.
GreenlightTestPrep wrote:
Carcass wrote:
\(x= \frac{1}{1+\frac{1}{1+\frac{1}{2}}}\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x |
1 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Key concept: 1/(a/b) = b/a
So, \(x= \frac{1}{1+\frac{1}{1+\frac{1}{2}}}\)
\(= \frac{1}{1+\frac{1}{\frac{2}{2}+\frac{1}{2}}}\)
\(= \frac{1}{1+\frac{1}{\frac{3}{2}}}\)
\(= \frac{1}{1+\frac{2}{3}}\)
\(= \frac{1}{\frac{3}{3}+\frac{2}{3}}\)
\(= \frac{1}{\frac{5}{3}}\)
\(= \frac{3}{5}\)
We get:
QUANTITY A: \(= \frac{3}{5}\)
QUANTITY B: \(1\)
Answer: B
Cheers,
Brent
