GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
On average, a sharpshooter hits the target once every 3 shot
[#permalink]
14 May 2019, 00:24
14 May 2019, 00:24
1
Expert Reply
5
Bookmarks
00:00
Question Stats:
45% (01:50) correct
54% (01:07) wrong based on 31 sessions
Hide Show timer Statistics
On average, a sharpshooter hits the target once every 3 shots. What is the probability that he will hit the target in 4 shots?
(A) \(1\)
(B) \(\frac{1}{81}\)
(C) \(\frac{1}{3}\)
(D) \(\frac{65}{81}\)
(E) \(\frac{71}{81}\)
(A) \(1\)
(B) \(\frac{1}{81}\)
(C) \(\frac{1}{3}\)
(D) \(\frac{65}{81}\)
(E) \(\frac{71}{81}\)
Re: On average, a sharpshooter hits the target once every 3 shot
[#permalink]
22 Aug 2019, 19:30
22 Aug 2019, 19:30
Carcass wrote:
On average, a sharpshooter hits the target once every 3 shots. What is the probability that he will hit the target in 4 shots?
(A) \(1\)
(B) \(\frac{1}{81}\)
(C) \(\frac{1}{3}\)
(D) \(\frac{65}{81}\)
(E) \(\frac{71}{81}\)
(A) \(1\)
(B) \(\frac{1}{81}\)
(C) \(\frac{1}{3}\)
(D) \(\frac{65}{81}\)
(E) \(\frac{71}{81}\)
Calculate the probability he will miss all 4 shots!
(2/3)^4 = 16/81 is the chance of missing all the shots.
So 1 - 16/81 is the change that hits it at least once.
Evaluates to 65/81
Answer is D.
gmatclubot
Re: On average, a sharpshooter hits the target once every 3 shot [#permalink]
22 Aug 2019, 19:30
Moderators:
