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Re: Miller sold apples at 125% of what it cost him. [#permalink]
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This problem is difficult as long as you do not know the % change in the various steps.

Cost price is 100. Selling price is 125

100 apples * 100 (cost)= 10,000

125*100 apples = 12,500

profit is 2,500

The selling price 125 the discount of 10% is 125 * 0.9 = 112,5 * 200 apples = 22,500

The cost of 100 apples * 200 = 20,000

The profit is equal.

The answer is C
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Re: Miller sold apples at 125% of what it cost him. [#permalink]
Carcass wrote:
Miller sold apples at 125% of what it cost him.

Quantity A
Quantity B
The profit made by selling 100 apples
The profit made by selling 200 apples at a further 10% discount


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Let the cost price of 1 apple be \(x\)
So, selling price of each apple is \(\frac{125}{100}x = 1.25x\)
After the discount of 10%, selling price of each apple = \(0.9(1.25x) = 1.125x\)

Profit = SP - CP

Col. A: \(100[1.25x - x] = 25x\)
Col. B: \(200[1.125x - x] = 25x\)

Hence, option C
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Re: Miller sold apples at 125% of what it cost him. [#permalink]
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