Useful remainder property:
When positive integer N is divided by positive integer D, the remainder R is such that 0 ≤ R < D
For example, if we divide some positive integer by 7, the remainder will be 6, 5, 4, 3, 2, 1, or 0

When j is divided by k, the remainder is m
The above property tells us that 0 ≤ m < k

When x is divided by y, the remainder is z
The above property tells us that 0 ≤ z < y

If ky = 75, which of the following CANNOT be the value of mz?
There are 3 ways in which ky = 75
1) k and y are 1 and 75
2) k and y are 3 and 25
3) k and y are 5 and 15

We can ELIMINATE case 1, because dividing by 1 will give us a remainder of 0, and we're told that all values are POSITIVE integers
So, k and y are EITHER 3 & 25 OR 5 & 15
So, we have two possible cases:
case a) m < 3 and k < 25
case b) m < 5 and k < 15

Now let's check the statements.
iii) 56
Are there values of m and z such that mz = 56, AND one of the two cases (above) are met?
YES!
If m = 4 and k = 14, then mk = (4)(14) = 56
This meets the conditions in case b. That is, m < 5 and k < 15
Since mz CAN equal 56, we can ELIMINATE answer choices A, C, D and E (since they say that mz CANNOT equal 56)

By the process of elimination, the correct answer is B

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