Re: A company produces 8 different types of candies
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01 May 2016, 01:09
Hi,
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Back to the question.
In this combinatorics problem, you must choose 3 candy from 8 possible choices. As such, we do have \(\frac{8!}{3!5!}=\)\(\frac{8*7*6*5*4*3*2*1}{3*2*1*5*4*3*2*1}\)
B is the answer.
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