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Re: Which of the following must be greater than x, where -1 < x [#permalink]
Expert Reply
Think x = 0.5 that is an exactly half way between -1 and zero.

-0.5 elevated to the third power becomes -0.125 that is on the number line is closer to zero than -0.5. Which means -0.125 is on the right side of -0.5


-1 ------------- -0.5 ----------------- - 0.125------------ zero

A is correct.

Hope this helps.

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Re: Which of the following must be greater than x, where -1 < x [#permalink]
thanks :-D


Carcass wrote:
Think x = 0.5 that is an exactly half way between -1 and zero.

-0.5 elevated to the third power becomes -0.125 that is on the number line is closer to zero than -0.5. Which means -0.125 is on the right side of -0.5


-1 ------------- -0.5 ----------------- - 0.125------------ zero

A is correct.

Hope this helps.

Regards
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Re: Which of the following must be greater than x, where -1 < x [#permalink]
IlCreatore wrote:
I am ok with all the answers but C. If x = -(1/2), then x^2+x = 1/4-1/2 = -1/2 that is equal to x. So it is not true that x^2+x must be greater than x.

Am I right? Or am I just tired that I do not get why C is ok?


if x=-1/2
then x^2+x= (-1/2*-1/2)+ (-1/2)
= 1/4-1/2
= -1/4 [ as the LCM of 2 and 4 is 4)
So, -1/4>-1/2
So, C
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Re: Which of the following must be greater than x, where -1 < x [#permalink]
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IlCreatore wrote:
I am ok with all the answers but C. If x = -(1/2), then x^2+x = 1/4-1/2 = -1/2 that is equal to x. So it is not true that x^2+x must be greater than x.

Am I right? Or am I just tired that I do not get why C is ok?


You're just tired :)
1/4 - 1/2 = -1/4 (not -1/2)

Cheers,
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Re: Which of the following must be greater than x, where -1 < x [#permalink]
Why B is incorrect?
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Which of the following must be greater than x, where -1 < x [#permalink]
1
ademeutia wrote:
Why B is incorrect?


B. \(\sqrt[3]{x}\)

\(\sqrt[3]{-\frac{1}{8}} = -\frac{1}{2}\) and \(-\frac{1}{2} < -\frac{1}{8}\)
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Which of the following must be greater than x, where -1 < x [#permalink]
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