amitmathew wrote:
Chocolates are packed in boxes that measure six inches long, three inches wide, and two inches high. If four individual boxes are packaged together in bulk by either arranging them in a single row or stacking them, what could be the total surface area of the bulk unit?
Indicate ALL that apply.
[ ] 168
[ ] 180
[ ] 192
[ ] 204
[ ] 252
[ ] 294
The total surface area ÷4*SA of one box = 4*2*(6*2+2*3+6*3)=4*2*36=288
Now let us check cases when they are in single row..
The base 6*3 will always be open to air
Case I..
The faces 2*3 are placed next to each other, so there will be 3 overlaps in four boxes with the result that SIX 3*2 faces will be eliminated while calculating SA
So 288-6*(2*3)=288-36=252
Case II..
The faces 2*6 are placed next to each other, so there will be 3 overlaps in four boxes with the result that SIX 6*2 faces will be eliminated while calculating SA
So 288-6*(2*6)=288-72=216
Now let us check cases when they are in single stack..
The base 6*3 will now be merged with each other
Case I..
The faces 6*3 are placed on top of each other, so there will be 3 overlaps in four boxes with the result that SIX 3*6 faces will be eliminated while calculating SA
So 288-6*(6*3)=288-108=180
So answer would be 180,216 and 252
But if stacking means they can be in form of 2*2, so nice it does not mention that they are stacked in one column, here four faces will be 6*3 that will be eliminated and other 4 will be
The two more cases..
Case 1.. when the overlap is 2*3 faces
So eliminated SA = 4*(2*3+6*3)=4*24=96
So SA = 288-96=192
Case 2.. when the overlap is 2*6 faces
So eliminated SA = 4*(2*6+6*3)=4*30=120
So SA = 288-120=168
So 168, 180, 192, 216, 252