GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If x > 0 and 2x-1=1/2x+1, then x=
[#permalink]
25 Jun 2019, 12:11
25 Jun 2019, 12:11
Expert Reply
00:00
Question Stats:
74% (01:11) correct
25% (01:18) wrong based on 79 sessions
Hide Show timer Statistics
If \(x > 0\) and \(2x-1=\frac{1}{2x+1}\), then \(x=\)
A. \(\frac{1}{2}\)
B. \(\frac{\sqrt{2}}{2}\)
C. \(1\)
D. \(\sqrt{2}\)
E. \(\sqrt{2} + 1\)
A. \(\frac{1}{2}\)
B. \(\frac{\sqrt{2}}{2}\)
C. \(1\)
D. \(\sqrt{2}\)
E. \(\sqrt{2} + 1\)
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If x > 0 and 2x-1=1/2x+1, then x=
[#permalink]
25 Jun 2019, 12:56
25 Jun 2019, 12:56
2
Carcass wrote:
If \(x > 0\) and \(2x-1=\frac{1}{2x+1}\), then \(x=\)
A. \(\frac{1}{2}\)
B. \(\frac{\sqrt{2}}{2}\)
C. \(1\)
D. \(\sqrt{2}\)
E. \(\sqrt{2} + 1\)
A. \(\frac{1}{2}\)
B. \(\frac{\sqrt{2}}{2}\)
C. \(1\)
D. \(\sqrt{2}\)
E. \(\sqrt{2} + 1\)
Given: \(2x-1=\frac{1}{2x+1}\)
Multiply both sides by \(2x+1\) to get: \((2x-1)(2x+1)=1\)
Expand and simplify to get: \(4x^2-1=1\)
Add 1 to both sides to get: \(4x^2=2\)
Divide both sides by 4 to get: \(x^2=\frac{2}{4}\)
Simplify to get: \(x^2=\frac{1}{2}\)
Since we're told \(x > 0\), we know that \(x = \sqrt{{\frac{1}{2}}}\)
= (√1)/(√2)
= 1/(√2)
= (√2)/2
Answer: B
Re: If x > 0 and 2x-1=1/2x+1, then x=
[#permalink]
31 Jan 2022, 22:11
31 Jan 2022, 22:11
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
