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xy are different from zero
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12 Jul 2019, 10:49
12 Jul 2019, 10:49
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Question Stats:
90% (00:29) correct
9% (01:16) wrong based on 143 sessions
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\(xy \neq 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(2 + \frac{1}{xy}\) |
\(\frac{2xy +1}{xy}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: xy are different from zero
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17 Sep 2019, 07:45
17 Sep 2019, 07:45
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QTY A: (2xy+1)/xy can be simplified this way.
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xy are different from zero
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06 Sep 2021, 10:23
06 Sep 2021, 10:23
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Carcass wrote:
\(xy \neq 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(2 + \frac{1}{xy}\) |
\(\frac{2xy +1}{xy}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Useful (and often tested) fraction property: \(\frac{a+b}{c} = \frac{a}{c} + \frac{b}{c}\)
When we apply the property to Quantity B we get:
QUANTITY B: \(\frac{2xy +1}{xy}=\frac{2xy}{xy}+\frac{1}{xy}\)
Simplify to get:
QUANTITY B: \(\frac{2xy}{xy}+\frac{1}{xy}=2+\frac{1}{xy}\)
Answer: C
