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x, y, and z are consecutive integers such that x < y < z.
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16 Jul 2019, 02:06
16 Jul 2019, 02:06
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x, y, and z are consecutive integers such that x < y < z.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(y\) |
\(\frac{x+z}{2}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: x, y, and z are consecutive integers such that x < y < z.
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15 Sep 2019, 17:39
15 Sep 2019, 17:39
1
Lets assume x = -1 and y = 0 and z = 1
Qty A: 0
Qty B : 0
Lets assume x=-2 and y = -1 and z=0
QTY A: -1
QTY B -1
Lets assume x = -3 and y = -2 and z = -1
QTY A: -2
QTY B: -2
Answer is C, based on all the three cases.
Qty A: 0
Qty B : 0
Lets assume x=-2 and y = -1 and z=0
QTY A: -1
QTY B -1
Lets assume x = -3 and y = -2 and z = -1
QTY A: -2
QTY B: -2
Answer is C, based on all the three cases.
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x, y, and z are consecutive integers such that x < y < z.
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16 Sep 2019, 07:24
16 Sep 2019, 07:24
1
Carcass wrote:
x, y, and z are consecutive integers such that x < y < z.
Quantity A |
Quantity B |
\(y\) |
\(\frac{x+z}{2}\) |
If x, y, and z are consecutive integers such that x < y < z, then we can write:
\(x = x\)
\(y = x + 1\)
\(z = x + 2\)
Replace given variables to get:
Quantity A: \(x+1\)
Quantity B: \(\frac{x+(x+2)}{2}\)
Simplify to get:
Quantity A: \(x+1\)
Quantity B: \(\frac{2x+2}{2}\)
Factor and simplify Quantity A to get:
Quantity A: \(x+1\)
Quantity B: \(\frac{2(x+1)}{2}=x+1\)
Answer: C
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