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Trail mix is made by combining 3 pounds of nuts that cost x
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19 Jul 2019, 02:13
19 Jul 2019, 02:13
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Trail mix is made by combining 3 pounds of nuts that cost x dollars per pound with 1 pound of chocolate that costs y dollars per pound and 2 pounds of dried fruit that costs z dollars per pound. What is the cost in dollars per pound for the trail mix?
A. \(\frac{3x+y+2x}{xyz}\)
B. \(3x+y+2z\)
C. \(\frac{3x+y+2z}{6}\)
D. \(6(3x+y+2z)\)
E. \(\frac{x}{3} + y + \frac{2}{z}\)
A. \(\frac{3x+y+2x}{xyz}\)
B. \(3x+y+2z\)
C. \(\frac{3x+y+2z}{6}\)
D. \(6(3x+y+2z)\)
E. \(\frac{x}{3} + y + \frac{2}{z}\)
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Re: Trail mix is made by combining 3 pounds of nuts that cost x
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20 Jul 2019, 06:40
20 Jul 2019, 06:40
2
Carcass wrote:
Trail mix is made by combining 3 pounds of nuts that cost x dollars per pound with 1 pound of chocolate that costs y dollars per pound and 2 pounds of dried fruit that costs z dollars per pound. What is the cost in dollars per pound for the trail mix?
A. \(\frac{3x+y+2x}{xyz}\)
B. \(3x+y+2z\)
C. \(\frac{3x+y+2z}{6}\)
D. \(6(3x+y+2z)\)
E. \(\frac{x}{3} + y + \frac{2}{z}\)
A. \(\frac{3x+y+2x}{xyz}\)
B. \(3x+y+2z\)
C. \(\frac{3x+y+2z}{6}\)
D. \(6(3x+y+2z)\)
E. \(\frac{x}{3} + y + \frac{2}{z}\)
3 pounds of nuts that cost x dollars per pound
Cost of 3 pounds of nuts = 3x
1 pound of chocolate that costs y dollars per pound
Cost of 1 pound of chocolate = y
2 pounds of dried fruit that costs z dollars per pound
Cost of 2 pounds of dried fruit = 2z
Total cost = 3x + y + 2z
Total weight = 3 + 1 + 2 = 6
What is the cost in dollars per pound for the trail mix?
Cost per pound = (total cost)/(total weight in pounds)
= (3x + y + 2z)/6
Answer: C
Cheers,
Brent
gmatclubot
Re: Trail mix is made by combining 3 pounds of nuts that cost x [#permalink]
20 Jul 2019, 06:40
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