GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Which is greater x/y or y/x
[#permalink]
Updated on: 22 Jul 2019, 02:27
Updated on: 22 Jul 2019, 02:27
1
2
Bookmarks
00:00
Question Stats:
67% (01:29) correct
32% (00:50) wrong based on 53 sessions
Hide Show timer Statistics
\(|x| \geq 1\)
\(|y| < \frac{1}{2}\)
\(x \neq 0\) and \(y \neq 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
\(|y| < \frac{1}{2}\)
\(x \neq 0\) and \(y \neq 0\)
Quantity A |
Quantity B |
\(\frac{x}{y}\) |
\(\frac{y}{x}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Originally posted by anuppatel012 on 20 Jul 2019, 22:07.
Last edited by Carcass on 22 Jul 2019, 02:27, edited 2 times in total.
Last edited by Carcass on 22 Jul 2019, 02:27, edited 2 times in total.
Edited by Carcass
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Which is greater x/y or y/x
[#permalink]
21 Jul 2019, 04:43
21 Jul 2019, 04:43
1
1
Bookmarks
anuppatel012 wrote:
\(|x| \geq 1\)
\(|y| < \frac{1}{2}\)
\(x \neq 0\) and \(y \neq 0\)
\(|y| < \frac{1}{2}\)
\(x \neq 0\) and \(y \neq 0\)
Quantity A |
Quantity B |
\(\frac{x}{y}\) |
\(\frac{y}{x}\) |
Let's test some possible values of x and y
case i: Since \(|x| \geq 1\) and \(|y| < \frac{1}{2}\), one possible pair of values is \(x=1\) and \(y=\frac{1}{3}\)
We get
Quantity A: \(\frac{1}{\frac{1}{3}}=3\)
Quantity B: \(\frac{\frac{1}{3}}{1}=\frac{1}{3}\)
In this case, Quantity A is greater
case ii: Another possible pair of values is \(x=-1\) and \(y=\frac{1}{3}\)
We get
Quantity A: \(\frac{-1}{\frac{1}{3}}=-3\)
Quantity B: \(\frac{\frac{1}{3}}{-1}=\frac{-1}{3}\)
In this case, Quantity B is greater
Answer: D
RELATED VIDEO
Re: Which is greater x/y or y/x
[#permalink]
21 Jul 2019, 04:48
21 Jul 2019, 04:48
Hi, is it possible to solve this using algebraic approach first and then substitute the values of x and y ?
