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Data set M = {60, 9, 10, 20, 12, 7, 10, 8}
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25 Dec 2018, 15:27
25 Dec 2018, 15:27
Expert Reply
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Question Stats:
81% (00:43) correct
18% (00:33) wrong based on 69 sessions
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Data set \(M = {60, 9, 10, 20, 12, 7, 10, 8}\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The mode of data set M |
The mean of data set M |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Given Kudos: 136
Data set M = {60, 9, 10, 20, 12, 7, 10, 8}
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09 May 2019, 09:04
09 May 2019, 09:04
2
Carcass wrote:
Data set \(M = {60, 9, 10, 20, 12, 7, 10, 8}\)
Quantity A |
Quantity B |
The mode of data set M |
The mean of data set M |
M = {7, 8, 9, 10, 10, 12, 20, 60}
The mode is the most frequently-occurring value(s).
So, mode = 10
Mean \(=\frac{7+8+9+10+10+12+20+60}{8}=\frac{136}{8}=17\)
We get:
QUANTITY A: 10
QUANTITY B: 17
Answer: B
RELATED VIDEO
Data set M = {60, 9, 10, 20, 12, 7, 10, 8}
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27 Jul 2019, 14:47
27 Jul 2019, 14:47
1
GreenlightTestPrep wrote:
Carcass wrote:
Data set \(M = {60, 9, 10, 20, 12, 7, 10, 8}\)
Quantity A |
Quantity B |
The mode of data set M |
The mean of data set M |
Arrange values in ASCENDING ORDER: M = {7, 8, 9, 10, 10, 12, 20, 60}
Since we have an EVEN number of values, the median = the average of the two middlemost values.
So, the median = (10 + 10)/2 = 20/2 = 10
The mode is the most frequently-occurring value(s).
So, mode = 10
We get:
QUANTITY A: 10
QUANTITY B: 10
Answer: C
RELATED VIDEO
quantity B is asking about mean not median! mean is definitely >10. The answer is B.
