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The seventh number in a sequence of numbers is 13 and each
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09 Aug 2019, 05:34
09 Aug 2019, 05:34
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Question Stats:
72% (00:52) correct
27% (00:33) wrong based on 33 sessions
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The seventh number in a sequence of numbers is \(31\) and each number after the first number in the sequence is \(4\) less than the number immediately preceding it. What is the fourth number in the sequence?
A. \(15\)
B. \(19\)
C. \(35\)
D. \(43\)
E. \(51\)
A. \(15\)
B. \(19\)
C. \(35\)
D. \(43\)
E. \(51\)
Re: The seventh number in a sequence of numbers is 13 and each
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09 Aug 2019, 05:36
09 Aug 2019, 05:36
Need explanation
Re: The seventh number in a sequence of numbers is 13 and each
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09 Aug 2019, 07:04
09 Aug 2019, 07:04
Expert Reply
As seventh number is 31 and each number is 4 less than the immediate previous number:
• Sixth number = 31 + 4 = 35
• Fifth number = 35 + 4 = 39
• Fourth number = 39 + 4 = 43
Hence, the correct answer is option D.
This is a GMAT question. You should use only GRE material, though.
Regards
• Sixth number = 31 + 4 = 35
• Fifth number = 35 + 4 = 39
• Fourth number = 39 + 4 = 43
Hence, the correct answer is option D.
This is a GMAT question. You should use only GRE material, though.
Regards
