Last visit was: 22 Dec 2024, 14:28 It is currently 22 Dec 2024, 14:28
Decision Tracker
My Rewards
New comers' posts
New posts
Unanswered

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more
Close

Request Expert Reply

Confirm Cancel
PREVIOUS TOPIC
NEXT TOPIC

To the nearest percent, by what percent did the population o

SORT BY:
Date
Kudos
Tags :
Find Similar Topics  About  Add a Tag

Show Tags
Hide Tags

User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30472
Own Kudos [?]: 36818 [4]
Given Kudos: 26100
Send PM
To the nearest percent, by what percent did the population o [#permalink] New post   22 May 2017, 01:05
Expert Reply
4
Bookmarks
00:00

Question Stats:

24% (02:27) correct 75% (02:07) wrong based on 62 sessions

Hide Show timer Statistics



Attachment:
#GREpracticequestion To the nearest percent, by what percent did the population of the United States increase from 1994 to 1998.jpg
#GREpracticequestion To the nearest percent, by what percent did the population of the United States increase from 1994 to 1998.jpg [ 57.93 KiB | Viewed 12564 times ]


To the nearest percent, by what percent did the population of the United States increase from 1994 to 1998?

A) 1%

B) 2%

C) 3%

D) 4%

E) 5%
ShowHide Answer
Official Answer
D
avatar
Pria
Intern
Intern
Joined: 28 Feb 2017
Posts: 6
Own Kudos [?]: 2 [0]
Given Kudos: 0
Send PM
Re: To the nearest percent, by what percent did the population o [#permalink] New post   24 Sep 2017, 20:52
1
Ans
Attachments

111itled.png
111itled.png [ 45.58 KiB | Viewed 14959 times ]

User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30472
Own Kudos [?]: 36818 [0]
Given Kudos: 26100
Send PM
Re: To the nearest percent, by what percent did the population o [#permalink] New post   25 Sep 2017, 02:38
Expert Reply
Please post your answer as text and your resoning. We solve together.

Do not post a screen.

Thank you
avatar
Avraheem
Intern
Intern
Joined: 14 Jun 2018
Posts: 36
Own Kudos [?]: 13 [0]
Given Kudos: 0
Send PM
Re: To the nearest percent, by what percent did the population o [#permalink] New post   01 Jul 2018, 10:05
Carcass wrote:
Please post your answer as text and your resoning. We solve together.

Do not post a screen.

Thank you


I agree Carcass, but why he assumed it was 1000 stolen vehicles? And why he assumed that the population must be increased?
User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30472
Own Kudos [?]: 36818 [3]
Given Kudos: 26100
Send PM
Re: To the nearest percent, by what percent did the population o [#permalink] New post   01 Jul 2018, 10:32
2
1
Expert Reply
The solution posted is partial, missing the last key sentence.

Quote:
Simplify the situation by assuming that in 1994 the population was 100,000 and there were 1000 vehicles stolen.The number of thefts per 100,000 inhabitants decreased 22.4% from 1000 to 776. So if there were 776 vehicles stolen for every 100,000 inhabitants, and 806 cars were stolen, the number of inhabitants must have increased. To know by how much, solve the proportion: \(\frac{776}{100,000}\) = \(\frac{806}{x}\) Cross-multiplying, we get \(776x = 80,600,000\). So, \(x = 103,800\). Then for every 100,000 inhabitants in 1994, there were 103,800 in 1998, an increase of \(3.8%\).


Ask for further assistance.

Regards
avatar
Avraheem
Intern
Intern
Joined: 14 Jun 2018
Posts: 36
Own Kudos [?]: 13 [1]
Given Kudos: 0
Send PM
Re: To the nearest percent, by what percent did the population o [#permalink] New post   02 Jul 2018, 00:17
1
Carcass wrote:
The solution posted is partial, missing the last key sentence.

Quote:
Simplify the situation by assuming that in 1994 the population was 100,000 and there were 1000 vehicles stolen. The number of thefts per 100,000 inhabitants decreased 22.4% from 1000 to 776. So if there were 776 vehicles stolen for every 100,000 inhabitants, and 806 cars were stolen, the number of inhabitants must have increased. To know by how much, solve the proportion: \(\frac{776}{100,000}\) = \(\frac{806}{x}\) Cross-multiplying, we get \(776x = 80,600,000\). So, \(x = 103,800\). Then for every 100,000 inhabitants in 1994, there were 103,800 in 1998, an increase of \(3.8%\).


Ask for further assistance.

Regards


I have got the general paradigm for solving this question as you can assume the initial number of stolen cars to be any number from 100 to 1 billion, but you will always get the same ratio always. But the logic of combining everything altogether and assuming that it increased is still vague to me.
User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30472
Own Kudos [?]: 36818 [0]
Given Kudos: 26100
Send PM
Re: To the nearest percent, by what percent did the population o [#permalink] New post   02 Jul 2018, 15:25
Expert Reply
I do not think honestly this is a good question.

Actually, you can perform the difference between 22.4 -19.4 = 3

However, considering that the population had a major increase during those years than the theft of the vehicle, the difference is not 3 but slightly more.

D is the answer. But is not a very clear question.
avatar
kruttikaaggarwal
Manager
Manager
Joined: 27 Feb 2017
Posts: 188
Own Kudos [?]: 148 [0]
Given Kudos: 0
Send PM
Re: To the nearest percent, by what percent did the population o [#permalink] New post   07 Aug 2018, 00:34
Is the question incomplete? There are no numbers to being with. How are assuming how many cars were stolen? How do we know 806 cars were stolen? i am so lost. Is this from an actual test?
User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30472
Own Kudos [?]: 36818 [0]
Given Kudos: 26100
Send PM
Re: To the nearest percent, by what percent did the population o [#permalink] New post   07 Aug 2018, 01:05
Expert Reply
You didnt read carefully the OE above.

It says that alike the previous question in the book you have to compute a % decrease.

Read now above, I have fixed it.

Hope now is more clear to you.

Regards
avatar
lakkiprudhvi
Intern
Intern
Joined: 09 Aug 2019
Posts: 6
Own Kudos [?]: 2 [0]
Given Kudos: 0
Send PM
Re: To the nearest percent, by what percent did the population o [#permalink] New post   09 Aug 2019, 19:22
carcass please the explain the question using other solution other than that is mentioned above
User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30472
Own Kudos [?]: 36818 [0]
Given Kudos: 26100
Send PM
Re: To the nearest percent, by what percent did the population o [#permalink] New post   10 Aug 2019, 11:54
Expert Reply
This is NOT a good question at a closer look.

The graph mentions of offenses in general and then the explanation talks about vehicles and cars which is not the same thing, strictly consider.

Practice with tons of questions on the board on the hard side yet OFFICIAL question. Do not waste your time here

Data Interpretation HARD questions

Regards
avatar
kabirstatdu
Intern
Intern
Joined: 15 Aug 2019
Posts: 31
Own Kudos [?]: 32 [0]
Given Kudos: 0
Send PM
Re: To the nearest percent, by what percent did the population o [#permalink] New post   16 Aug 2019, 07:11
1
Is there missing any info ?
I think, enough data is not exist here.
avatar
Ronoray
Intern
Intern
Joined: 25 Nov 2020
Posts: 1
Own Kudos [?]: 4 [4]
Given Kudos: 0
Send PM
Re: To the nearest percent, by what percent did the population o [#permalink] New post   09 Dec 2020, 07:48
4
Percentage of cases in 94 = (Number of cases in 94)/(Population in 94)*100 - (1)
Percentage of cases in 98 = (Number of cases in 98)/(Population in 98)*100 - (2)

Percentage of cases in 98 = (100-22.4)/100 * (Percentage of cases in 94) - (3)
Number of cases in 98 = (100-19.4)/100 * (Number of cases in 94) - (4)

Substituting (3) and (4) in (2)

77.6/100 * (Percentage of cases in 94) = 80.6/100 * (Number of cases in 94)/(Population in 98)*100 - (5)

Divide (5) by (1) to get the following

77.6 = 80.6 * (Population in 94)/(Population in 98)

(Population in 98)/(Population in 94) = 1.03866

Subtract 1 from both sides
(Population in 98)/(Population in 94)-1= 1.03866-1
[(Population in 98)-(Population in 94)]/(Population in 94) = 0.03866

So the percentage change is 0.03866*100 = 3.866% = approximately 4% (D)

It took me way too long to come up with the logic of how to solve this problem!
User avatar
bumpbot
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5089
Own Kudos [?]: 76 [0]
Given Kudos: 0
Send PM
Re: To the nearest percent, by what percent did the population o [#permalink] New post   05 Aug 2024, 23:59
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderators:
adewale223
GRE Instructor
88 posts
bronaugust
GRE Forum Moderator
37 posts
BrushMyQuant
Moderator
1115 posts
VibhuAnurag
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Main navigation

Partners

GRE Resources

www.ets.org/gre | About | Terms and Conditions and Privacy Policy | Prep Club for GRE Rules | Contact