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The numbers {a,b,c} are three positive integers.
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03 Sep 2019, 03:08
03 Sep 2019, 03:08
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The numbers {a,b,c} are three positive integers. If \(\frac{(a×b×c)}{14}\) equals an integer and \(\frac{(b×c)}{4}\) equals an integer, what is the smallest possible integer value of a?
A. \(1\)
B. \(2\)
C. \(4\)
D. \(7\)
E. \(14\)
A. \(1\)
B. \(2\)
C. \(4\)
D. \(7\)
E. \(14\)
Re: The numbers {a,b,c} are three positive integers.
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03 Sep 2019, 08:09
03 Sep 2019, 08:09
Expert Reply
Setting the two conditions \(\frac{a \times b \times c}{14}\) AND \(\frac{b \times c}{14}\) we do know that \(b\times c\) must be a multiple of 14: 14,28, so forth.
The question boils down to the value of a in the fraction above. To continue to have an integer a must be equal to 1 as minimum value to get the overall fraction an integer
Regards
The question boils down to the value of a in the fraction above. To continue to have an integer a must be equal to 1 as minimum value to get the overall fraction an integer
Regards
Re: The numbers {a,b,c} are three positive integers.
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03 Sep 2019, 21:00
03 Sep 2019, 21:00
Carcass wrote:
Setting the two conditions \(\frac{a \times b \times c}{14}\) AND \(\frac{b \times c}{14}\) we do know that b\times c must be a multiple of 14: 14,28, so forth.
The question boils down to the value of a in the fraction above. To continue to have an integer a must be equal to 1 as minimum value to get the overall fraction an integer
Regards
The question boils down to the value of a in the fraction above. To continue to have an integer a must be equal to 1 as minimum value to get the overall fraction an integer
Regards
still confuse
