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Re: x is an integer and x>1
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10 Jun 2021, 19:07
x is an integer and x>1
Column A
\(\sqrt{64x^2+36x^2}\) = \(\sqrt{x^2(64+36)}\)
= \(\sqrt{100x^2}\) \(\sqrt{(10x)^2}\)
= |10x| [As square root of a number is always positive]
= 10 * |x|
Now, we know that x > 1 => |x| = x
=> 10|x| = 10x
Now, x is an integer greater than 1, so x can be 2, 3,...
=> 10x can we be 10*2, 10*3,...
=> 10x can we be 20,30,....
Column B
20
Now, Column A can be 20 or greater than 20 too.
So, column A can be = Column B or can be greater than Column B too.
So, Answer will be Option D "Answer Cannot be determined"
Hope it helps!