Thank you, this explained it well!

a and b are positive integers such that 4<a+b<6 and |a−b|=1

A+B has to be 5 since A & B Are integers and the absolute value equation has to be equal to 1.

Two numbers that satisfy this are 2 and 3.

Now:
The volume of a cylinder with radius a and height b
The volume of a cylinder with radius b and height a

We don't know which is 2 and which is 3. The one with Radius 3 will be greater than Radius 2.

Answer D.

For completeness:

Pi(3^2)*2 = 18pi
Pi(2^2)*3= 12pi

\(a + b = 5\)

So, we can have \(a = 1, 2, 3,\) or \(4\) and \(b = 4, 3, 2,\) or \(1\)

Also, \(|a - b| = 1\)

i.e. \(|1 - 4| = 1\)
\(|2 - 3| = 1\)
\(|3 - 2| = 1\)
\(|4 - 1| = 1\)

Col. A: \(πa^2b\)
Col. B: \(πb^2a\)

Dividing both sides by \(πab\):

Col. A: \(a\)
Col. B: \(b\)

When \(a = 2\) and \(b = 3\), Col. A < Col. B
When \(a = 3\) and \(b = 2\), Col. A > Col. B

Hence, option D