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a * b = ab/a+b for all a, b that satisfy a is different from

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a * b = ab/a+b for all a, b that satisfy a is different from [#permalink] New post   19 Jul 2019, 09:32
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\(a \circ b = \frac{ab}{a+b}\) for all a, b that satisfy \(a ≠ -b\). What is the value of \((–4) \circ 2\)?

A. \(-4\)

B. \(-2\)

C. \(-\frac{4}{3}\)

D. \(\frac{4}{3}\)

E. \(4\)
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Re: a * b = ab/a+b for all a, b that satisfy a is different from [#permalink] New post   20 Sep 2019, 14:41
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(-4)°2= ((-4)(2))/(-4+2)= (-8)/(-2)=4
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Re: a * b = ab/a+b for all a, b that satisfy a is different from [#permalink] New post   07 Aug 2022, 23:27
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Given that \(a \circ b = \frac{ab}{a+b}\) and we need to find the value of \((–4) \circ 2\)

To find \((–4) \circ 2\) we need to compare what is before and after \(\circ\) in \((–4) \circ 2\) and \(a \circ b\)

=> We need to substitute a with -4 and b with 2 in \(a \circ b = \frac{ab}{a+b}[/m to get the value of [m](–4) \circ 2\)

=> \(-4 \circ 2 = \frac{-4*2}{-4+2}\) = \(\frac{-8}{-2}\) = 4

So, Answer will be E
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a * b = ab/a+b for all a, b that satisfy a is different from [#permalink] New post   09 Jun 2023, 21:28
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Since \(a \circ b = \frac{ab}{a+b}\)

\(-4 \circ 2 = \frac{-4(2)}{-4+2} = \frac{-8}{-2} = 4\)

The answer is E
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a * b = ab/a+b for all a, b that satisfy a is different from [#permalink]
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