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ABCD is a rectangle.
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25 Sep 2019, 15:40
25 Sep 2019, 15:40
Expert Reply
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Question Stats:
64% (00:43) correct
35% (00:30) wrong based on 14 sessions
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ABCD is a rectangle.
E is the intersection of AD and BC.
Quantity A |
Quantity B |
The area of \(\triangle CED\) |
The area of \(\triangle AEC\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: ABCD is a rectangle.
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02 Oct 2019, 08:03
02 Oct 2019, 08:03
1
Answer is C, both are equal
Let length be L and Width be W.
The two diagonals bisect at the centre.
Area of CED = 1/2 * base *height =1/2* L * W/2 = LW/4
Area of AEC = 1/2 * W * L/2 = LW/4
Thus both are same
Let length be L and Width be W.
The two diagonals bisect at the centre.
Area of CED = 1/2 * base *height =1/2* L * W/2 = LW/4
Area of AEC = 1/2 * W * L/2 = LW/4
Thus both are same
gmatclubot
Re: ABCD is a rectangle. [#permalink]
02 Oct 2019, 08:03
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