HarveyKlaus wrote:
The vertices of square S have coordinates (-1,-2), (-1,1), (2,1), and (2,-2) respectively. What are the coordinates of the point where the diagonals of S intersect?
a) (1/2, 1/2)
b) (1/2, -1/2)
c) (3/2, 1/2)
d) (3/2, -1/2)
e) (underoot3/2, 1/2)
The easiest way to go about this question is to sketch it and identify which are the diagonally opposite vertices. However there is a shorter way to accomplish the same.
We know that diagonals of a square bisect each other. So in a square ABCD, the coordinates of the point where the diagonals of ABCD intersect.
A+C2=B+D2or coordinates of the point where the diagonal intersects can be written as =
A+B+C+D4.
So
x=−1−1+2+24=12y=−2+1+1−24=−12.
Hence option B is correct!