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Dick takes twice as long as Jane to run any given distance.
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Updated on: 08 Oct 2019, 15:08
Updated on: 08 Oct 2019, 15:08
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64% (01:53) correct
35% (02:00) wrong based on 53 sessions
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Dick takes twice as long as Jane to run any given distance.
Starting at the same moment, Dick and Jane run towards each other from opposite ends of the schoolyard, a total distance of x, at their respective constant rates until they meet
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Starting at the same moment, Dick and Jane run towards each other from opposite ends of the schoolyard, a total distance of x, at their respective constant rates until they meet
Quantity A |
Quantity B |
The fraction of the total distance x that is covered by Jane |
\({\frac{2}{3}}x\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: Dick takes twice as long as Jane to run any given distance.
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08 Oct 2019, 12:02
08 Oct 2019, 12:02
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pranab01 wrote:
Dick takes twice as long as Jane to run any given distance. Starting at the same moment, Dick and Jane run towards each other from opposite ends of the schoolyard, a total distance of x, at their respective constant rates until they meet
Quantity A |
Quantity B |
The fraction of the total distance x that is covered by Jane |
\({\frac{2}{3}}x\) |
GIVEN: Dick takes twice as long as Jane to run any given distance.
In other words, Jane travels TWICE as fast as Dick does.
So, for every 1 meter that Dick travels, Jane travels 2 meters.
GIVEN: Starting at the same moment, Dick and Jane run towards each other from opposite ends of the schoolyard, a total distance of x, at their respective constant rates until they meet
This is a CLOSING GAP question.
So, for every 1 meter that Dick travels towards Jane, Jane travels 2 meters towards Dick.
In other words, every time the gap closes by 3 units of length, Jane travels 2 units and Dick travels 1 unit.
Since the initial gap is x, we know that the total COMBINED distances traveled by Dick and Jane is x.
This means Dick traveled 1/3 of x, and Jane traveled 2/3 of x
We get:
QUANTITY A: 2/3 of x
QUANTITY B: (2/3)x
Answer: C
Cheers,
Brent
General Discussion
Re: Dick takes twice as long as Jane to run any given distance.
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08 Oct 2019, 10:56
08 Oct 2019, 10:56
any solutions for this?
