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A carpenter get an order to
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09 Oct 2019, 00:36
09 Oct 2019, 00:36
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47% (00:54) correct
52% (01:51) wrong based on 19 sessions
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A carpenter get an order to cut boards to a length of 4.750 m. The average length of the cut boards is 4.750 m, and the errors in cutting are normally distributed. Which of the following individually would provide sufficient information to determine what percentage of the cut boards are greater than 4.705 m in length?
Indicate all such statements.
A)The median length of the cut boards is the same as the mean length.
B)The standard deviation of the errors in cutting the boards is 0.002 m.
C)Sixteen percent of the boards were less than or equal to 4.748 m in length.
D)Inspectors reject any board shorter than 4.690 m.
Indicate all such statements.
A)The median length of the cut boards is the same as the mean length.
B)The standard deviation of the errors in cutting the boards is 0.002 m.
C)Sixteen percent of the boards were less than or equal to 4.748 m in length.
D)Inspectors reject any board shorter than 4.690 m.
Re: A carpenter get an order to
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09 Oct 2019, 00:36
09 Oct 2019, 00:36
How can we specify the standard deviation from answer C ?
Re: A carpenter get an order to
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23 Oct 2019, 10:08
23 Oct 2019, 10:08
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Asmakan wrote:
How can we specify the standard deviation from answer C ?
Refer to the attached picture.
For a normally distributed data, it is known that approximately 34% data fall around 1 standard deviation away from mean, further 14% 2 s.d away, further 2% 3 s.d away. Since we are given that "Sixteen percent of the boards were less than or equal to 4.748 m in length.", refers to the region(on the graph) to the left of (mean - 2 s.d) as that region has the 16% of total data.
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