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If a right triangle has area 28 and hypotenuse 12, what is i
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31 Oct 2019, 02:43
31 Oct 2019, 02:43
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31% (02:10) wrong based on 16 sessions
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If a right triangle has area 28 and hypotenuse 12, what is its perimeter?
A. 20
B. 24
C. 28
D. 32
E. 36
A. 20
B. 24
C. 28
D. 32
E. 36
Re: If a right triangle has area 28 and hypotenuse 12, what is i
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31 Oct 2019, 02:44
31 Oct 2019, 02:44
Let the legs of this right triangle be \(x\) and \(y\).
Given: \(area=\frac{xy}{2}=28\) --> \(xy=56\) and \(hypotenuse=x^2+y^2=12^2\).
Question: \(P=x+y+12=?\), so we should calculate the value of \(x+y\).
Square \(x+y\) --> \((x+y)^2=x^2+2xy+y^2\). As \(xy=56\) and \(x^2+y^2=12^2\), then: \((x+y)^2=x^2+2xy+y^2=12^2+2*56=256\) --> \(x+y=\sqrt{256}=16\).
\(P=x+y+12=16+12=28\).
Answer: C
Given: \(area=\frac{xy}{2}=28\) --> \(xy=56\) and \(hypotenuse=x^2+y^2=12^2\).
Question: \(P=x+y+12=?\), so we should calculate the value of \(x+y\).
Square \(x+y\) --> \((x+y)^2=x^2+2xy+y^2\). As \(xy=56\) and \(x^2+y^2=12^2\), then: \((x+y)^2=x^2+2xy+y^2=12^2+2*56=256\) --> \(x+y=\sqrt{256}=16\).
\(P=x+y+12=16+12=28\).
Answer: C
Re: If a right triangle has area 28 and hypotenuse 12, what is i
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10 Mar 2023, 09:38
10 Mar 2023, 09:38
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
