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\frac{[square_root]3[/square_root] + [square_root]2[/square_
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17 Apr 2019, 01:53
17 Apr 2019, 01:53
Expert Reply
00:00
Question Stats:
77% (01:11) correct
22% (01:01) wrong based on 54 sessions
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Quantity A |
Quantity B |
\(\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3}- \sqrt{2}}\) |
\(\frac{\sqrt{5} + \sqrt{2}}{\sqrt{5} - \sqrt{2}}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: \frac{[square_root]3[/square_root] + [square_root]2[/square_
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01 Nov 2019, 16:17
01 Nov 2019, 16:17
1
Quantity A = (1.732+1.414)/(1.732-1.414)= 3.146/0.318=9.89
Quantity B: (2.236+1.414)/(2.236-1.414)=3.65/0.822=4.44
Option A is correct.
Quantity B: (2.236+1.414)/(2.236-1.414)=3.65/0.822=4.44
Option A is correct.
Re: \frac{[square_root]3[/square_root] + [square_root]2[/square_
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05 Nov 2019, 10:56
05 Nov 2019, 10:56
1
Carcass wrote:
Quantity A |
Quantity B |
\(\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3}- \sqrt{2}}\) |
\(\frac{\sqrt{5} + \sqrt{2}}{\sqrt{5} - \sqrt{2}}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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