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The area of a circle with radius a is less than the area of
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07 Nov 2019, 10:50
07 Nov 2019, 10:50
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Question Stats:
67% (01:15) correct
32% (01:23) wrong based on 85 sessions
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The area of a circle with radius \(a\) is less than the area of a square with sides of length \(ka\). Which of the following could be the value of k?
Indicate all such values.
A. \(\frac{4}{3}\)
B. \(\frac{5}{3}\)
C. \(\frac{6}{3}\)
D. \(\frac{7}{3}\)
Indicate all such values.
A. \(\frac{4}{3}\)
B. \(\frac{5}{3}\)
C. \(\frac{6}{3}\)
D. \(\frac{7}{3}\)
Re: The area of a circle with radius a is less than the area of
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23 Nov 2019, 16:58
23 Nov 2019, 16:58
1
Area of the circle a²*pi
area of the square a²k²
k² is greater than pi
k is greater than the square root of pi
Answer is C and D (both greater than or equal to the square root of pi)
area of the square a²k²
k² is greater than pi
k is greater than the square root of pi
Answer is C and D (both greater than or equal to the square root of pi)
Re: The area of a circle with radius a is less than the area of
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14 Jun 2020, 06:20
14 Jun 2020, 06:20
1
The area of a circle with radius a is less than the area of a square with sides of length ka. Which of the following could be the value of k?
Area of circle = pi * \(r^2\)
where r = a
so Area = pi * \(a^2\)
Area of square = \(Side^2\)
so Area of square = \(k^2\) * \(a^2\)
equate together,
pi * \(a^2\) = \(k^2\) * \(a^2\)
simplify
pi=\(k^2\)
we know that, pi = 3.142
so search for those given values of k that prove pi<k^2
only 6/3 and 7/3 are those values
Area of circle = pi * \(r^2\)
where r = a
so Area = pi * \(a^2\)
Area of square = \(Side^2\)
so Area of square = \(k^2\) * \(a^2\)
equate together,
pi * \(a^2\) = \(k^2\) * \(a^2\)
simplify
pi=\(k^2\)
we know that, pi = 3.142
so search for those given values of k that prove pi<k^2
only 6/3 and 7/3 are those values
