GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The average (arithmetic mean) of the two numbers 3x and 3y i
[#permalink]
25 Nov 2019, 08:08
25 Nov 2019, 08:08
1
Expert Reply
00:00
A
B
C
D
Question Stats:
86% (00:39) correct
13% (00:13) wrong based on 66 sessions
Show timer Statistics
The average (arithmetic mean) of the two numbers 3x and 3y is 48.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The average (arithmetic mean) of the two numbers 2x and 2y |
30 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: The average (arithmetic mean) of the two numbers 3x and 3y i
[#permalink]
28 Nov 2019, 11:05
28 Nov 2019, 11:05
1
The answer is A
(3x + 3y)/2 =48
=>3x+3y = 96
=>x+y =32
A = (2x +2y )/2
= 2(x+y)/2
=x+y
=32
So A is bigger
(3x + 3y)/2 =48
=>3x+3y = 96
=>x+y =32
A = (2x +2y )/2
= 2(x+y)/2
=x+y
=32
So A is bigger
Re: The average (arithmetic mean) of the two numbers 3x and 3y i
[#permalink]
06 Apr 2020, 13:45
06 Apr 2020, 13:45
AAAAA
